A) \[{{N}_{2}}\]
B) \[C{{O}_{2}}\]
C) \[{{H}_{2}}\]
D) \[{{O}_{2}}\]
Correct Answer: D
Solution :
\[2N{{a}_{2}}{{O}_{2}}+2{{H}_{2}}O\xrightarrow{{}}4NaOH+{{O}_{2}}\]. Thus in this reaction, oxygen \[({{O}_{2}})\] is formed.
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