A) \[{{f}_{1}}={{f}_{2}}\]and\[d=\frac{2}{3}{{f}_{1}}\]
B) \[{{f}_{1}}=3{{f}_{2}}\]and\[d={{f}_{1}}+{{f}_{2}}\]
C) \[{{f}_{1}}={{f}_{2}}\]and\[d={{f}_{1}}+{{f}_{2}}\]
D) \[{{f}_{1}}=\frac{2}{3}{{f}_{2}}\]and\[d=\frac{2}{3}{{f}_{1}}\]
Correct Answer: A
Solution :
Ramsdens eye piece contains the field lens and eye lens of same focal lengths and both the lenses are separated by a distance\[\frac{2f}{3}\], hence,\[{{f}_{1}}={{f}_{2}}\]and\[d=\frac{2}{3}{{f}_{1}}\].
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