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Punjab Medical Punjab - MET Solved Paper-1999

  • question_answer
    The radius of circular path of an electron when subjected to a perpendicular magnetic field, will be

    A) \[\frac{mv}{Be}\]                                            

    B) \[\frac{me}{B}\]

    C) \[\frac{mE}{B}\]                                              

    D) \[\frac{Be}{mv}\]

    Correct Answer: A

    Solution :

    Centripetal force on the electron\[=\frac{m{{v}^{2}}}{r}\] Force on moving charge in the magnetic field is\[=Bev\] Hence\[\frac{m{{v}^{2}}}{r}=Bev\]or\[r=\frac{mv}{Be}\]


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