A) \[0.125\times {{10}^{15}}\]
B) \[0.5\times {{10}^{10}}\]
C) \[0.5\times {{10}^{15}}\]
D) \[0.25\times {{10}^{10}}\]
Correct Answer: C
Solution :
\[Ca{{(OH)}_{2}}\rightleftharpoons {{\underset{s}{\mathop{Ca}}\,}^{+2}}+{{\underset{2s}{\mathop{OH}}\,}^{-}}\] \[pH=9\text{ }pOH=5\] \[[O{{H}^{}}]={{10}^{5}}=2s\] \[s=\frac{{{10}^{-5}}}{2}\] \[{{K}_{sp}}=\text{(s)}O{{H}^{}}^{2}\] \[=\frac{{{10}^{-5}}}{2}\times {{({{10}^{-5}})}^{2}}\] \[\frac{1}{2}\times {{10}^{-15}}\] \[=0.5\times {{10}^{15}}\]
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