A) \[{{C}_{2}}\]
B) \[B{{e}_{2}}\]
C) \[{{O}_{2}}\]
D) \[{{N}_{2}}\]
Correct Answer: A
Solution :
\[{{C}_{2}}=\sigma 1{{s}^{2}}\text{ }\sigma *\text{ }1{{s}^{2}}\text{ }\sigma 2{{s}^{2}}\text{ }\sigma *2{{s}^{2}}\text{ }\] \[\pi 2p_{x}^{2}\,\pi 2p_{y}^{2}\] 12 \[{{e}^{-}}\] has only \[\pi \] bonds according to M.O.T. In \[{{C}_{2}}\]molecule, only \[\pi \]electron occupied the bonding molecular orbital.
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