A) \[12.2\times {{10}^{14}}m\]
B) 12.2 nm
C) \[12.2\times {{10}^{13}}m\]
D) \[12.2\times {{10}^{12}}m\]
Correct Answer: D
Solution :
\[\lambda =\frac{12.27}{\sqrt{V}}\overset{\text{o}}{\mathop{\text{A}}}\,=\frac{12.27}{\sqrt{10,000}}\overset{\text{o}}{\mathop{\text{A}}}\,\] \[=12.27\times {{10}^{2}}\overset{\text{o}}{\mathop{\text{A}}}\,\] \[=12.27\times {{10}^{12}}m\]
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