A) \[H{{g}_{2}}{{l}_{2}},{{l}^{-}}\]
B) \[Hg{{l}_{2}},l_{3}^{-}\]
C) \[Hg{{l}_{2}},{{l}^{-}}\]
D) \[Hgl_{4}^{2-},l_{3}^{-}\]
Correct Answer: D
Solution :
In a solution containing \[HgC{{l}_{2}},{{l}_{2}}\]and \[{{l}^{-}},\] both \[HgC{{l}_{\,}}_{2}\]and \[{{l}_{2}}\]compete for\[{{l}^{-}}.\] Since formation constant of \[{{[Hg{{l}_{4}}]}^{2-}}\] \[1.9\times {{10}^{30}}\] which is very large as compared with \[{{l}_{3}}^{-}({{K}_{f}}=700)\] \[\therefore \]\[{{l}^{-}}\]will preferentially combine with \[HgC{{l}_{2}}.\] \[HgC{{l}_{2}}+2{{l}^{-}}\to \underset{\text{Red}\,\text{ppt}}{\mathop{Hg{{l}_{2}}\downarrow +2C{{l}^{-}}}}\,\] \[Hg{{l}_{2}}+2{{l}^{-}}\to \underset{So\operatorname{lub}le}{\mathop{{{[Hg{{l}_{4}}]}^{2-}}}}\,\]
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