A) \[{{P}_{2}}{{O}_{5}}\]
B) \[C{{O}_{2}}\]
C) \[S{{O}_{2}}\]
D) \[N{{O}_{2}}\]
Correct Answer: C
Solution :
\[S{{O}_{2}}\] is readily decolourises acidified \[KMn{{O}_{4}}.\]
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