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NEET NEET SOLVED PAPER 2017

  • question_answer
    The two nearest harmonics of a tube closed at one end and open at other end are 220 Hz and 260 Hz. What is the fundamental frequency of the system?                                                                               

    A)  40 Hz                   

    B)  10 Hz

    C)   20 Hz                  

    D)   30 Hz

    Correct Answer: C

    Solution :

                     Two successive frequencies of closed pipe \[\frac{nv}{4l}=220\]                                      ?(i) \[\frac{(n+2)}{4l}=260\]                ?(ii) Dividing (ii) by (i), we get \[\frac{n+2}{n}=\frac{260}{220}=\frac{13}{11}\] \[11n+22=13n\] \[n=11\] So,                          \[11\frac{v}{4l}=220\]                                 \[\frac{v}{4l}=20\] So fundamental frequency is 20 Hz.


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