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NEET NEET SOLVED PAPER 2016 Phase-I

  • question_answer
    When an \[\alpha -\]particle of mass 'm' moving with velocity 'v' bombards on a heavy nucleus of charge 'Ze', its distance of closest approach from the nucleus depends on m as :                                            

    A)  \[\frac{1}{m}\]                                

    B)  \[\frac{1}{\sqrt{m}}\]

    C)  \[\frac{1}{{{m}^{2}}}\]                                 

    D)   m

    Correct Answer: A

    Solution :

                     At closest distance of approach, the kinetic energy of the particle will convert completely into electrostatic potential energy. \[\Rightarrow \]               \[\frac{1}{2}m{{v}^{2}}=\frac{KQq}{d}\Rightarrow d\propto \frac{1}{m}\]


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