A) \[{{\text{U}}_{1}}=0\]
B) \[{{\text{U}}_{3}}=0\]
C) \[{{\text{U}}_{\text{1}}}\text{ }{{\text{U}}_{\text{2}}}\]
D) \[{{\text{U}}_{2}}\text{ }{{\text{U}}_{1}}\]
Correct Answer: D
Solution :
Maximum amount of emitted radiation corresponding to \[{{\lambda }_{m}}=\frac{b}{T}\] \[{{\lambda }_{m}}=\frac{2.88\times {{10}^{6}}\,nmK}{5760K}=500\,nm\] From the graph \[{{\text{U}}_{\text{1}}}\text{ }{{\text{U}}_{\text{2}}}\text{ }{{\text{U}}_{\text{3}}}\]You need to login to perform this action.
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