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NEET NEET SOLVED PAPER 2016 Phase-I

  • question_answer
    Consider the junction diode as ideal. The value of current flowing through AB is :                             

    A)  \[0\,A\]                                              

    B)  \[{{10}^{-2}}A\]

    C)   \[{{10}^{-1}}A\]                             

    D)   \[{{10}^{-3}}A\]

    Correct Answer: B

    Solution :

                     Since diode is in forward bias\[i=\frac{\Delta V}{R}=\frac{4-(-6)}{1\times {{10}^{3}}}=\frac{10}{{{10}^{3}}}={{10}^{-2}}A\]


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