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NEET NEET SOLVED PAPER 2016 Phase-I

  • question_answer
    In a diffraction pattern due to a single slit of width 'a', the first minimum is observed at an angle \[{{30}^{o}}\] when light of wavelength \[5000\text{ }\overset{o}{\mathop{\text{A}}}\,\] is incident on the slit. The first secondary maximum is observed at an angle of :

    A)  \[{{\sin }^{-1}}\left( \frac{1}{4} \right)\]                               

    B)  \[{{\sin }^{-1}}\left( \frac{2}{3} \right)\]

    C)   \[{{\sin }^{-1}}\left( \frac{1}{2} \right)\]                              

    D)   \[{{\sin }^{-1}}\left( \frac{3}{4} \right)\]

    Correct Answer: D

    Solution :

                     For first minima, \[\sin {{30}^{o}}=\frac{\lambda }{a}=\frac{1}{2}\] First secondary maxima will be at \[\sin \theta =\frac{3\lambda }{2a}=\frac{3}{2}\left( \frac{1}{2} \right)\Rightarrow \theta ={{\sin }^{-1}}\left( \frac{3}{4} \right)\]


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