A) \[\Delta G=-2.30RT\,\log K\]
B) \[\Delta G=2.30RT\,\log K\]
C) \[\Delta {{G}^{{}^\circ }}=-2.30RT\,\log K\]
D) \[\Delta {{G}^{{}^\circ }}=2.30RT\,\log K\]
Correct Answer: C
Solution :
Mathematical expression of the thermodynamic equilibrium is \[\Delta G=\Delta {{G}^{\text{o}}}\,+2.303RT\operatorname{logQ}\] At equilibrium when \[\Delta G=0\] and Q = K then \[\Delta G=\Delta {{G}^{{}^\circ }}+2.303RT\log K=0\] \[\Delta {{G}^{{}^\circ }}=-2.303RT\log K\]
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