A) OR
B) NAND
C) AND
D) NOR
Correct Answer: C
Solution :
The truth table for the given circuit is| A | B | \[{{\mathbf{y}}_{\mathbf{1}}}\] | \[{{\mathbf{y}}_{\mathbf{2}}}\] | \[\mathbf{y=}\overset{\mathbf{\_\_\_\_\_\_\_\_}}{\mathop{{{\mathbf{y}}_{\mathbf{1}}}\mathbf{+}{{\mathbf{y}}_{\mathbf{2}}}}}\,\] |
| 0 | 0 | 1 | 1 | 0 |
| 0 | 1 | 1 | 0 | 0 |
| 1 | 0 | 0 | 1 | 0 |
| d1 | 1 | 0 | 0 | 1 |
You need to login to perform this action.
You will be redirected in
3 sec
