NEET NEET SOLVED PAPER 2015 (C)

  • question_answer
    In a double slit experiment, the two slits are 1 mm apart and the screen is placed 1 m away. A monochromatic light of wavelength 500 nm is used. What will be the width of each slit for obtaining ten maxima of double slit within the central maxima of single slit pattern.                                                                                      

    A)   0.2 mm              

    B)  0.1 mm               

    C)  0.5 mm               

    D)  0.02 mm

    Correct Answer: A

    Solution :

    Given \[d=1\,mm=1\times {{10}^{-3}}m\] \[D=1m\] \[\lambda =500nm=5\times {{10}^{-7}}m\] As width of central maxima = width of 10 maxima \[\therefore \]                  \[\frac{2D\lambda }{a}\,=10\,\left( \frac{\lambda D}{d} \right)\] \[\Rightarrow \]               \[a=\frac{d}{5}\,=\frac{{{10}^{-3}}}{5}\,=0.2\,\times {{10}^{-3}}\,m\] \[a=0.2\,mm\]


You need to login to perform this action.
You will be redirected in 3 sec spinner