A) 8 : 16 : 1
B) 16 : 8 : 1
C) 16 : 1: 2
D) 8 : 1 : 2
Correct Answer: C
Solution :
According to Avogadro's hypothesis, Volume of a gas (V) \[\propto \] number of moles (n) Therefore, the ratio of the volumes of gases can be determined in terms of their moles. The ratio of volumes of \[{{H}_{2}}\] : \[{{O}_{2}}\] : methane \[(C{{H}_{4}})\] is given by \[{{V}_{{{H}_{2}}:}}{{V}_{{{O}_{2}}}}:{{V}_{C{{H}_{4}}}}={{n}_{{{H}_{2}}}}:{{n}_{{{O}_{2}}}}:{{n}_{C{{H}_{4}}}}\] Þ \[{{V}_{{{H}_{2}}}}:{{V}_{{{O}_{2}}}}:{{V}_{C{{H}_{4}}}}=\frac{{{m}_{{{H}_{2}}}}}{{{M}_{{{H}_{2}}}}}:\frac{{{m}_{{{O}_{2}}}}}{{{M}_{{{O}_{2}}}}}:\frac{{{m}_{C{{H}_{4}}}}}{{{M}_{C{{H}_{4}}}}}\] But \[{{m}_{{{H}_{2}}}}={{m}_{{{O}_{2}}}}={{m}_{C{{H}_{4}}}}=m\left[ \because \,n=\frac{mass}{molar\,mass} \right]\] Thus, \[{{V}_{{{H}_{2}}}}:{{V}_{{{O}_{2}}}}:{{V}_{C{{H}_{4}}}}=\frac{m}{2}:\frac{m}{32}:\frac{m}{16}=16:1:2\]
You need to login to perform this action.
You will be redirected in
3 sec
