NEET NEET SOLVED PAPER 2014

  • question_answer
    A transformer having efficiency of 90% is working on 200 V and 3 kW power supply. If the current in the secondary coil is 6 A, the voltage across the secondary coil and the current in the primary coil respectively are  [AIPMT 2014]

    A)  300 V, 15 A       

    B)  450 V, 15 A

    C)  450 V, 13.5 A     

    D)  600 V, 15 A

    Correct Answer: B

    Solution :

    Initial power = 3000 W As efficiency is 90% then final power \[=3000\times \frac{90}{100}\] \[=2700W\] \[\Rightarrow \] \[\left. \begin{align}   & {{V}_{1}}{{l}_{1}}=3000W \\  & {{V}_{1}}{{l}_{1}}=2700W \\ \end{align} \right]\,\,\,\,\,\,\,\,\,\,\,\,......(i)\] So, \[{{V}_{2}}\frac{2700}{6}=\frac{900}{2}=450V\] and \[{{l}_{1}}\frac{3000}{200}=15A\]


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