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NEET Physics Work, Energy, Power & Collision / कार्य, ऊर्जा और शक्ति NEET PYQ-Work Energy Power and Collision

  • question_answer
    A uniform force of \[(3\mathbf{i}+\mathbf{j})\,N\] acts on a particle of mass 2 kg. Hence the particle is displaced from position \[(2\mathbf{i}+\mathbf{k})\,m\] to position \[(4\mathbf{i}+3\mathbf{j}-\mathbf{k})\,m\]. The work done by the force on the particle is [NEET 2013]

    A) 9 J

    B) 6 J

    C) 13 J

    D) 15 J

    Correct Answer: A

    Solution :

    Given, force \[F=3i+j\]
    \[{{r}_{1}}=(2i+k)m\] and \[{{r}_{2}}=(4i+3J-k)m\]
    \[\therefore \]      \[s={{r}_{2}}-{{r}_{1}}=(4i+3j-k)-(2i+k)\]
    \[=(2i+3j-2k)m\]
    \[\therefore \]      \[W=F\cdot s=(3i+j)\cdot (2i+3j-2k)\]
                            \[=3\times 2+\,3+0\]
                            \[=6+3=9\,J\]


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