A) 6.25%
B) 20%
C) 26.8%
D) 12.5%
Correct Answer: C
Solution :
| [c] Efficiency of ideal heat engine, \[\eta \text{=}\left( \text{1-}\frac{{{\text{T}}_{\text{2}}}}{{{\text{T}}_{\text{1}}}} \right)\] |
| \[{{\text{T}}_{\text{2}}}\] : Sink temperature |
| \[{{\text{T}}_{1}}\] : Source temperature |
| \[%\eta \text{=}\left( \text{1-}\frac{{{\text{T}}_{\text{2}}}}{{{\text{T}}_{\text{1}}}} \right)\text{ }\!\!\times\!\!\text{ 100}\] |
| \[=\left( 1-\frac{273}{373} \right)\times 100\] |
| \[=\left( \frac{100}{373} \right)\times 100=26.8%\] |
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