NEET Physics Thermodynamical Processes NEET PYQ-Thermodynamical Processes

  • question_answer
    A thermodynamic system is taken through the cycle ABCD as shown in figure. Heat rejected by the gas during the cycle is              [AIPMT (S) 2012]

    A)  \[2\,pV\]

    B)       \[4\,pV\]

    C)  \[\frac{1}{2}pV\]         

    D)       \[pV\]

    Correct Answer: A

    Solution :

               
    For given cyclic process, \[\Delta U=0\]
    \[\therefore \]      \[Q=W\]
    Also,     \[W=-\] area enclosed by the curve
                \[=AB\times AD\]
                \[=(2p-p)(3V-V)\]
    \[=-p\times 2V\]
    \[\therefore \]      Heat rejected \[=\,2\,pV\]


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