A) 28 atm
B) 68.7 atm
C) 256 atm
D) 8 atm
Correct Answer: C
Solution :
| \[{{T}_{i}}=273+27=300\,K\] |
| \[{{T}_{2}}=273+927=1200\,K\] |
| Gas equation for adiabatic process \[p{{V}^{\gamma }}\] constant |
| \[p{{\left( \frac{T}{p} \right)}^{\gamma }}=\text{constant}\] \[(\because pV=RT)\] |
| \[\therefore \] \[\frac{{{p}_{2}}}{{{p}_{1}}}={{\left( \frac{{{T}_{2}}}{{{T}_{1}}} \right)}^{\frac{\gamma }{\gamma -1}}}\] or \[{{p}_{2}}={{p}_{1}}{{\left( \frac{{{T}_{2}}}{{{T}_{1}}} \right)}^{\frac{\gamma }{\gamma -1}}}\] |
| \[{{p}_{2}}=2{{\left( \frac{1200}{300} \right)}^{\frac{1.4}{1.4-1}}}\] |
| \[{{p}_{2}}=256\,\text{atm}\] |
You need to login to perform this action.
You will be redirected in
3 sec
