A) \[6.66\,\,kg\,\,{{m}^{2}}{{s}^{-2}}\]
B) \[8.58\,\,kg\,\,{{m}^{2}}{{s}^{-2}}\]
C) \[10.86\,\,kg\,\,{{m}^{2}}{{s}^{-2}}\]
D) \[2.86\,\,kg\,\,{{m}^{2}}{{s}^{-2}}\]
Correct Answer: A
Solution :
| As velocity of an automobile vehicle, |
| \[v=54km/hr=54\times \frac{5}{18}=15m/s\] |
| Angular velocity of a vehicle, \[v={{\omega }_{0}}r\] |
| \[\Rightarrow \] \[{{\omega }_{0}}=\frac{v}{R}=\frac{15}{0.45}=\frac{100}{3}rad/s\] |
| So, angular acceleration of an automobile, |
| \[\alpha =\frac{\Delta \omega }{t}=\frac{{{\omega }_{t}}-{{\omega }_{0}}}{t}=\frac{0-\frac{100}{3}}{15}=\frac{-100}{45}rad/{{s}^{2}}\] |
| Thus, average torque transmitted by its brakes to wheel |
| \[\tau =I\alpha \] |
| \[\Rightarrow \] \[3\times \frac{100}{45}=6.66\,\,kg\,\,{{m}^{2}}{{s}^{-2}}\] |
| Physics for medical Entrance (Digvijay Singh) we needed for attempting medium difficult questions. |
| When mica is introduced, capacitance will increase hence voltage across capacitor, get decrease. |
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