2. Solved Papers
  3. NEET
  4. Physics
  5. NLM, Friction, Circular Motion

NEET Physics NLM, Friction, Circular Motion NEET PYQ-NLM Friction Circular Motion

  • question_answer
    Two racing cars of masses \[{{m}_{1}}\] and \[{{m}_{2}}\] are moving in circles of radii \[{{r}_{1}}\] and \[{{r}_{2}}\] respectively. Their speeds are such that each makes a complete circle in the same time t. The ratio of the angular speeds of the first to the second car is: [AIPMT 1999]

    A) 1 : 1

    B) \[{{m}_{1}}:\text{ }{{m}_{2}}\]

    C) \[{{r}_{1}}:\text{ }{{r}_{2}}\]

    D) \[{{m}_{1}}:\text{ }{{m}_{2}}:\text{ }{{r}_{1}}{{r}_{2}}\]

    Correct Answer: A

    Solution :

    Angular speed
                \[\frac{\text{Angle}\,\text{traversed}\,\text{in}\,\text{one}\,\text{revolution}}{\text{Time-period}}\]
                So,       \[\omega =\frac{2\pi }{t}\]
                As T is same for both racing cars, therefore angular speed to is same for both cars.
                i.e.,       \[\frac{{{\omega }_{1}}}{{{\omega }_{2}}}=1\]
                or           \[{{\omega }_{1}}\,:\,{{\omega }_{2}}=1:1\]


You need to login to perform this action.
You will be redirected in 3 sec spinner