NEET Physics NLM, Friction, Circular Motion NEET PYQ-NLM Friction Circular Motion

  • question_answer
    A 500 kg car takes a round turn of radius 50 m with a velocity of 36 km/h. The centripetal force is: [AIPMT 1999]

    A) 250 N

    B) 750 N

    C) 1000 N

    D) 1200 N

    Correct Answer: C

    Solution :

    The centripetal force required for a car (mass m) to take a sharp turn of radius r with velocity v is
                            \[F=\frac{m{{v}^{2}}}{r}\]
                Given,   \[m=500\text{ }kg,\]
                \[v=36\text{ }km/h=36\times \frac{5}{18}=10\,m/s\,,\,r=50\,m\]
                Hence,      \[F=\frac{500\times {{(10)}^{2}}}{50}=1000\,N\]


You need to login to perform this action.
You will be redirected in 3 sec spinner