A) 1 : 14
B) 1 : 6
C) 1 : 9
D) 1 : 11
Correct Answer: D
Solution :
| [d] Spring constant \[\propto \frac{1}{\text{length}}\] |
| \[k\propto \frac{1}{l}\] |
| i.e., \[{{k}_{1}}=6k\] |
| \[{{k}_{2}}=3k\] |
| \[{{k}_{3}}=2k\] |
| In series |
| \[\frac{1}{k'}=\frac{1}{6k}+\frac{1}{3k}+\frac{1}{2k}\] |
| \[\frac{1}{k'}=\frac{6}{6k}\] |
| \[k'=k\] |
| \[k''=6k+3k+2k\] |
| \[k''=11k\] |
| \[\frac{k'}{k''}=\frac{1}{11}\] i.e., \[k':k''=1:11\] |
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