A) \[\sqrt{g{{R}^{2}}\frac{{{u}_{s}}+\tan \theta }{1-{{\mu }_{s}}\tan \theta }}\]
B) \[\sqrt{gR\frac{{{u}_{s}}+\tan \theta }{1-{{\mu }_{s}}\tan \theta }}\]
C) \[\sqrt{\frac{g}{R}\frac{{{u}_{s}}+\tan \theta }{1-{{\mu }_{s}}\tan \theta }}\]
D) \[\sqrt{\frac{g}{{{R}^{2}}}\frac{{{u}_{s}}+\tan \theta }{1-{{\mu }_{s}}\tan \theta }}\]
Correct Answer: B
Solution :
[b] \[\frac{{{v}^{2}}}{Rg}=\left( \frac{{{\mu }_{s}}+\tan \theta }{1-{{\mu }_{s}}\tan \theta } \right)\] \[\Rightarrow \] \[v=\sqrt{Rg\left[ \frac{{{\mu }_{s}}+\tan \theta }{1-{{\mu }_{s}}\tan \theta } \right]}\]
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