NEET Physics NLM, Friction, Circular Motion NEET PYQ-NLM Friction Circular Motion

A player takes 0.1 s in catching a ball of mass 150 g moving with velocity of 20 m/s. The force imparted by the ball on the hands of the player is: [AIPMT 2001]

A) 0.3 N

B) 3 N

C) 30 N

D) 300 N

Correct Answer: C

Solution :

Key Idea: The force imparted (or impulse) by the ball to the hands of the player is equal to the rate of change of linear momentum.

Force imparted = Rate of change of momentum

or \[F=\frac{\Delta p}{\Delta t}\]

or \[F=\frac{{{p}_{1}}-{{p}_{2}}}{\Delta t}\]

or \[F=\frac{m({{v}_{1}}-{{v}_{2}})}{\Delta t}\]

Here,

\[m=150\text{ }g=0.150\text{ }kg,\text{ }{{v}_{1}}=20\text{ }m/s,\text{ }{{v}_{2}}=0\]

\[\Delta t=0.1\,\,s\]

\[\therefore \] \[F=\frac{0.150\times (20-0)}{0.1}=30\,N\]