A) x
B) \[\frac{383}{283}x\]
C) \[\frac{10}{110}x\]
D) \[\frac{283}{383}x\]
Correct Answer: D
Solution :
| Writing ideal gas law |
| \[PV=nRT\] |
| or \[PV=\frac{m}{M}RT\] |
| or \[\frac{PV}{m}=\frac{1}{M}RT\] |
| or \[\frac{P}{\rho }=\frac{RT}{M}\] |
| or \[\frac{\rho }{P}=\frac{1}{T}\] |
| \[\therefore \] \[\frac{{{\rho }_{1}}/{{p}_{1}}}{{{\rho }_{2}}/{{p}_{2}}}=\frac{{{T}_{2}}}{{{T}_{1}}}\] |
| \[\Rightarrow \] \[\frac{x}{({{\rho }_{2}}/{{p}_{2}})}=\frac{383}{283}\] |
| or \[\frac{{{\rho }_{2}}}{{{p}_{2}}}=\frac{283}{383}x\] |
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