JEE Main & Advanced Physics Electrostatics & Capacitance NEET PYQ - Electrostatics and Capacitance

When a proton is accelerated through 1V its kinetic energy will be: [AIPMT 1999]

A) 1540 eV

B) 13.6 eV

C) 1 eV

D) zero

Correct Answer: C

Solution :

[c] When a proton is accelerated through 1V, its kinetic energy

\[K=qV\]

For a proton, \[q=e=1.6\times {{10}^{-19}}\,C\]

and \[V=1\text{ }volt\]

Thus, \[K=(1.6\times {{10}^{-19}}\times 1)\,J=1\,eV\]

(as \[1\,eV=1.6\times {{10}^{-19}}\,J\])