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MGIMS WARDHA MGIMS WARDHA Solved Paper-2015

  • question_answer
    A beam of monochromatic light is incident on one face of an equilateral prism. The angle of incidence is\[55{}^\circ \]. If the angle of emergence is \[46{}^\circ \], then the angle of minimum deviation\[{{\delta }_{m}}\]will be

    A)  \[>41{}^\circ \]                

    B)  \[<41{}^\circ \]

    C)  \[=41{}^\circ \]                                

    D)  \[\ge 41{}^\circ \]

    Correct Answer: B

    Solution :

                    Given \[A=60{}^\circ \] \[e=46{}^\circ \Rightarrow i=55{}^\circ \] Since,                 \[i+e=A+\delta \] \[\Rightarrow \]               \[55+46=60+\delta \] \[\Rightarrow \]               \[\delta =41{}^\circ \] Practically the angle of minimum deviation for a glass prism is less than\[40{}^\circ \](about\[38{}^\circ \]or\[39{}^\circ \]) So,             \[\delta <41{}^\circ \]


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