A) \[1.56\times {{10}^{-5}}T\]
B) \[1.62\times {{10}^{-4}}T\]
C) \[1.42\times {{10}^{-6}}T\]
D) \[1.88\times {{10}^{-5}}T\]
Correct Answer: C
Solution :
The magnetic field will provide the necessary centripetal force to the electron. i.e., \[{{F}_{cp}}={{F}_{m}}\] \[\Rightarrow \] \[\frac{m{{v}^{2}}}{r}=qvB\sin 90{}^\circ \] \[B=\frac{mv}{e.r}=\frac{9.1\times {{10}^{-31}}\times {{10}^{5}}}{1.6\times {{10}^{-19}}\times 0.4}\] \[\Rightarrow \] \[=\frac{91}{64}\times {{10}^{-6}}=142\times {{10}^{-6}}T\]
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