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MGIMS WARDHA MGIMS WARDHA Solved Paper-2015

  • question_answer
    The electric field in a region is given by\[E=(4\hat{i}+3\hat{j})V/m\]. The net flux passing through a square area of side 4 m parallel to 4 y-z plane is

    A)  32 V-m                                

    B)  16 V-m

    C)  12 V-m                                

    D)  64 V-m

    Correct Answer: D

    Solution :

                    A square area of side 4 m parallel to y-z plane in vector form can be written as \[S={{4}^{2}}\hat{i}=16\hat{i}{{m}^{2}}\] Given,    \[E=(4\hat{i}+3\hat{j})v{{m}^{-1}}\] Electric flux passing through the given area is                 \[{{\phi }_{E}}=E.S\]                 \[=(4\hat{i}+3\hat{j}).16\hat{i}=64\,V-m\]


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