A) \[1.24\times {{10}^{-4}}J\]
B) \[1.76\times {{10}^{-5}}J\]
C) \[1.8\times {{10}^{-3}}J\]
D) \[2.4\times {{10}^{-4}}J\]
Correct Answer: B
Solution :
Given that \[T=28\times {{10}^{-2}}N{{m}^{-1}},d=1\,cm\] \[r=\frac{1}{2}cm=0.005\,m\] \[\therefore \]Area of sphere \[A=4\pi {{r}^{2}}\] As the soap bubble has two free surfaces, So, work done\[=T.2A\] \[=2.8\times {{10}^{-2}}\times 2\times 4\times 3.14\times {{(0.005)}^{2}}\] \[=28\times 314\times 8\times 25\times {{10}^{-5}}\times {{10}^{-6}}\] \[\approx 1.76\times {{10}^{-5}}J\]
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