A) \[{{F}_{E}}>{{F}_{G}}\]
B) \[{{F}_{N}}>{{F}_{E}}\]
C) \[{{F}_{E}}>>{{F}_{G}}\]
D) \[{{F}_{N}}>>{{F}_{G}}\]
Correct Answer: C
Solution :
For two electrons at a separation r \[\frac{{{F}_{E}}}{{{F}_{G}}}=\frac{\frac{1}{4\pi {{\varepsilon }_{0}}}.\frac{{{e}^{2}}}{{{r}^{2}}}}{G\frac{m_{e}^{2}}{{{r}^{2}}}}=\frac{9\times {{10}^{9}}\times {{(1.6\times {{10}^{-19}})}^{2}}}{6.67\times {{10}^{-11}}\times {{(9.1\times {{10}^{-31}})}^{2}}}\] \[\frac{{{F}_{E}}}{{{F}_{G}}}=4.17\times {{10}^{42}}\] Hence, \[{{F}_{E}}>>{{F}_{G}}\] As total force on an electron is \[F={{F}_{E}}+{{F}_{G}}={{F}_{E}}\]
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