A) Fe is oxidised to\[F{{e}^{2+}}\]and dissolved oxygen in water is reduced to\[O{{H}^{-}}\]
B) Fe is oxidised to\[F{{e}^{3+}}\]and\[{{H}_{2}}O\]is reduced to\[O_{2}^{2-}\]
C) Fe is oxidised to\[F{{e}^{2+}}\]and\[{{H}_{2}}O\]is reduced to
D) Fe is oxidised to\[F{{e}^{2+}}\]and\[{{H}_{2}}O\]is reduced to\[{{O}_{2}}\]
Correct Answer: A
Solution :
\[Fe\xrightarrow[{}]{{}}F{{e}^{2+}}+2{{e}^{-}}\] (anode reaction) \[{{O}_{2}}+2{{H}_{2}}O+4{{e}^{-}}\xrightarrow[{}]{{}}4O{{H}^{-}}\] (cathode reaction) The overall reaction is \[2Fe+{{O}_{2}}+2{{H}_{2}}\text{O}\xrightarrow{{}}2Fe{{(OH)}_{2}}\] \[Fe{{(OH)}_{2}}\]may be dehydrated to iron oxide \[FeO\]. or further oxidised of\[Fe{{(OH)}_{3}}\]and then dehydrated to iron rust,\[F{{e}_{2}}{{O}_{3}}\].
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