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MGIMS WARDHA MGIMS WARDHA Solved Paper-2014

  • question_answer
    0.5 mole of each of\[{{H}_{2}},S{{O}_{2}}\]and\[C{{H}_{4}}\]are kept in a container. A hole was made in the container. After 3 h, the order of partial pressures in the container will be

    A)  \[pS{{O}_{2}}>p{{H}_{2}}>pC{{H}_{4}}\]

    B)  \[pS{{O}_{2}}>pC{{H}_{4}}>p{{H}_{2}}\]

    C)  \[p{{H}_{2}}>pS{{O}_{2}}>pC{{H}_{4}}\]

    D)  \[p{{H}_{2}}>pC{{H}_{4}}>pS{{O}_{2}}\]

    Correct Answer: B

    Solution :

                    Rate of diffusion \[\propto \frac{1}{\sqrt{molecular\text{ }mass}}\] \[\therefore \]Order of diffusion \[{{H}_{2}}>C{{H}_{4}}>S{{O}_{2}}\] and amount left is in the order: \[S{{O}_{2}}>C{{H}_{4}}>{{H}_{2}}\] Hence, order of partial pressure is \[pS{{O}_{2}}>pC{{H}_{4}}>p{{H}_{2}}\]


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