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MGIMS WARDHA MGIMS WARDHA Solved Paper-2014

  • question_answer
    If the phase difference between two points is \[60{}^\circ \]on a wave velocity of 360 m/s and frequency 500 Hz, then path difference between the two points is

    A)  1 cm                                     

    B)  6 cm

    C)  12cm                                   

    D)  24cm

    Correct Answer: C

    Solution :

                    The wavelength\[\lambda =\frac{v}{f}=\frac{360\times 100}{500}=72\,cm\] Path difference \[=\frac{\lambda }{2\pi }\times \]phase difference                 \[=\frac{\lambda }{2\pi }\times \frac{\pi }{3}=\frac{\lambda }{6}=12\,cm\]


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