The speed of the ball when it reaches the horizontal part of the surface is
A) \[{{v}_{0}}=\sqrt{gh}\]
B) \[{{v}_{0}}=\sqrt{5gh}\]
C) \[{{v}_{0}}=\sqrt{2gh}\]
D) None of these
Correct Answer: C
Solution :
The speed of the ball, when it reaches the horizontal part of the surface is \[{{w}_{net}}=\Delta k\] \[mgh+0=\frac{1}{2}mv_{0}^{2}-0\] \[{{v}_{0}}=\sqrt{2gh}\]
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