2. Solved Papers
  3. MGIMS WARDHA

MGIMS WARDHA MGIMS WARDHA Solved Paper-2014

  • question_answer
    If the equation for the displacement of a particle moving on a circular path is given by \[\theta =2{{t}^{3}}+0.5,\]where\[\theta \]is in radian and t in second, then the angular velocity of the particle after 2 s from its start is

    A)  8 rad/s                

    B)  12 rad/s

    C)  24 rad/s              

    D)  36 rad/s

    Correct Answer: C

    Solution :

                    Since,\[\theta =2{{t}^{3}}+0.5,\]the angular velocity of the particle\[=\frac{d\theta }{dt}=6{{t}^{2}},\] At\[t=2\text{ }s,\]angular velocity\[=6\times 22=24\text{ }rad/s\]


You need to login to perform this action.
You will be redirected in 3 sec spinner