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MGIMS WARDHA MGIMS WARDHA Solved Paper-2013

  • question_answer
    In the refining of silver by electrolytic method, what will be the weight of 100 g Ag anode if 5A current is passed for hours? The purity of silver anode is 95% by weight.

    A)  42.91 g                

    B)  57.59 g

    C) 13.69g                  

    D)  36.38 g

    Correct Answer: B

    Solution :

                    Only pure Ag from the anode is oxidised, which in turn is deposited at cathode. By Faradays first law, weight of Ag deposited at cathode, \[W=Zit\]                 \[=\frac{108\times 5\times 2\times 3600}{1\times 96500}=40.29\,g\] but anode is 95% pure w.r.t., Ag. Hence, actual loss is \[=40.29\times \frac{100}{95}=42.41\text{ }g\] Weight of Ag-anode after electrolysis \[=100-42.41=57.59\text{ }g\]


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