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MGIMS WARDHA MGIMS WARDHA Solved Paper-2013

  • question_answer
    When 2.495 g of\[CuS{{O}_{4}}.x{{H}_{2}}O\](molar mass 249.5) is heated, 0.05 mole of\[{{H}_{2}}O\]is lost. Therefore,\[x\]is

    A)  one                      

    B)  three   

    C)  five                      

    D)  seven

    Correct Answer: C

    Solution :

                    Number of moles of \[CuS{{O}_{4}}.x{{H}_{2}}O\] \[=\frac{2.495}{249.5}=0.01mole\] \[\therefore \]Moles of\[{{H}_{2}}O\]                   \[=0.01\times mole\] \[=0.05\]mole


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