A) \[SiC{{l}_{4}}\]
B) \[NH_{4}^{+}\]
C) \[{{N}_{2}}{{O}_{4}}\]
D) \[S{{F}_{4}}\]
Correct Answer: D
Solution :
\[S{{F}_{4}}\]has trigonal bipyramid geometry since it has\[s{{p}^{3}}d\]hybridisation.
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