A) \[I<II<III\]
B) \[I<III<II\]
C) \[III<II<I\]
D) \[II<III<I\]
Correct Answer: D
Solution :
Presence of electron donating group at o-position w.r.t. \[Cl\]decreases reactivity to a greater extent than at\[m-\]position. Thus, correct arrangement is\[II<III<I\].
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