A) 1788
B) 1192
C) 596
D) 298
Correct Answer: C
Solution :
\[I=\frac{B}{{{\mu }_{0}}}-H\] \[B={{\mu }_{0}}H(1+{{\chi }_{m}})\] \[{{\chi }_{m}}=\frac{\mu }{{{\mu }_{0}}}-I\] \[\phi =2.4\times {{10}^{-5}}Wb,\] \[A=0.2\times {{10}^{-4}}{{m}^{2}}\] \[B=\frac{\phi }{A}=\frac{2.4\times {{10}^{-5}}}{0.2\times {{10}^{-4}}}=1.2\,Wb/{{m}^{2}}\] \[\mu =\frac{B}{H}=\frac{1.2}{1600}=7.5\times {{10}^{-4}}H/{{m}^{2}}\] \[{{\chi }_{m}}=\frac{7.5\times {{10}^{-4}}}{4\pi \times {{10}^{-7}}}-I=596\]
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