MGIMS WARDHA MGIMS WARDHA Solved Paper-2013

  • question_answer
    A balloon contains\[500\text{ }{{m}^{3}}\]of He at\[27{}^\circ C\]and 1 atmospheric pressure. The volume of He at \[-3{}^\circ C\] and\[0.5\] atmospheric pressure will be

    A)  \[700{{m}^{3}}\]                             

    B)  \[900{{m}^{3}}\]

    C)  \[1000\,{{m}^{3}}\]                       

    D)  \[500{{m}^{3}}\]

    Correct Answer: B

    Solution :

                    Using standard gas equation \[\frac{{{p}_{1}}{{V}_{1}}}{{{T}_{1}}}=\frac{{{p}_{2}}{{V}_{2}}}{{{V}_{2}}}\]           \[\Rightarrow \]                \[{{V}_{2}}=\frac{{{p}_{1}}{{V}_{1}}{{T}_{2}}}{{{p}_{2}}{{T}_{1}}}\] \[{{V}_{2}}=\frac{1\times 500\times (273-3)}{0.5\times (273+27)}\]                 \[{{V}_{2}}=\frac{1\times 500\times 273}{0.5\times 300}\] \[\Rightarrow \]\[{{V}_{2}}=900\,{{m}^{2}}\]


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