A) \[{{10}^{-4}}\]
B) 0.01
C) 0.001
D) 0.1
Correct Answer: A
Solution :
\[\underset{s}{\mathop{Ag}}\,Cl\underset{s}{\mathop{A{{g}^{+}}}}\,+\underset{s}{\mathop{C{{l}^{-}}}}\,\] Solubility =1.435 g/L Solubility \[=\frac{1.435}{143.5}mol/L\] 143.5 = molecular weight Solubility product\[={{(s)}^{2}}\] \[={{(0.01)}^{2}}={{10}^{-4}}\]
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