A) 1 moles of \[{{H}_{2}}\]
B) 2 mole of \[{{H}_{2}}\]
C) \[\frac{1}{2}\]mole of \[{{H}_{2}}\]
D) All of the above
Correct Answer: C
Solution :
\[C{{H}_{3}}OH+Na\xrightarrow[{}]{{}}C{{H}_{3}}ONa+\frac{1}{2}{{H}_{2}}\] 23 g Na forms ... \[\frac{1}{2}\]mole of\[{{H}_{2}}\]
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