A) 0.01 M
B) 2 M
C) 0.4 M
D) 0.02 M
Correct Answer: A
Solution :
\[pH=-\log [{{H}^{+}}]\] \[2=-\log [{{H}^{+}}]\] \[[{{H}^{+}}]={{10}^{-2}}=0.01\,M\]
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