2. Solved Papers
  3. MGIMS WARDHA

MGIMS WARDHA MGIMS WARDHA Solved Paper-2012

  • question_answer
    The amount of heat required to change 1 g \[(0{}^\circ C)\]of ice into water of\[100{}^\circ C,\]is

    A)  716 cal                                 

    B)  500 cal

    C)  180 cal                                 

    D)  100 cal

    Correct Answer: C

    Solution :

                    Heat required to convert\[0{}^\circ C\]of ice in water \[=mL\] (L = latent heat) Now, heat required to rise the temperature of water from\[0{}^\circ C\]to\[100{}^\circ C\]. \[=ms\Delta t\] where\[s=\]specific heat.\[\Delta t=\]temperature difference. Total heat\[=mL+ms\Delta t\] \[=1\times 80+1\times 1\times (100-0)\] \[=180cal\]


You need to login to perform this action.
You will be redirected in 3 sec spinner